How to Make a Random Number Generator Using Visual Basic 2012


Introduction: How to Make a Random Number Generator Using Visual Basic 2012

hi in this instructable i'm going to show you how to make a random number generator
first open the visual basic program
then drag a button onto the form
and add a text box
next double click on the button
and once you're in the code building page, input this code line:
Dim a as Integer
Dim value As Integer = CInt(Int((10 * Rnd()) + 1))
TextBox1.Clear()
' Initialize the random-number generator.
Randomize()
' Generate random value between 0 and 600.
TextBox1.Text = CInt(Int((10 * Rnd()) + 1))
a = TextBox1.Text
once you input this code you should be able to generate a random number and you can also change to code to make it generate larger numbers
I want to say thank you to all of my followers and i didn't expect to make it this far, and everything i do on here i do for you guys thank you.
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Visual Basic generate random number
I am new to coding and I want to make a simple program that moves a windows to a random location on your desktop. Right now my code is this:
I had to put in the code myself so it will never be completely random and will always repeat itself. How do I make the numbers a random number?
- 1 msdn.microsoft.com/en-us/library/system.random(v=vs.110).aspx if you use Stack Overflow as your search engine you're going to have a bad time. – user1228 Jul 25, 2017 at 12:36
- Dim random As New Random then you can use it as random.Next() . A little of this would have helped you. Eminem wouldn't be proud of you Stan! – boop_the_snoot Jul 25, 2017 at 12:39
- 1 Is google down? No! – Onic Team Jul 25, 2017 at 12:40
- Simple stuff really: i.imgur.com/vea0apD.png But you should consider using Google or even search here on SO for the answer before you ask, since basic stuff like this has probably been answered before. – Alexander Johansen Jul 25, 2017 at 12:52
2 Answers 2
First declare this variable in the scope of the class:
Then put this code in whatever event you want to use to set the window to a random position:
This will also make sure that the window will always stay within the bounds of the screen when put to a new random position.

You would probably want to use the Rnd() function
Rnd() generates a number n, 0<= n < 1 so if you want to generate a number between 1 and 10, you need to add +1, as multiplying Rnd() with 10 will give you numbers between 0 and 9.

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How to generate a random number in Visual Basic 6?
Table of Contents
- 1 How to generate a random number in Visual Basic 6?
- 2 How to use randomize with the same value for number?
- 3 How does the randomize function in vbmath work?
- 4 How to generate a random value in vbmath?
- 5 How to initialize a random number generator in Visual Basic?
Write a program in visual basic 6 that will ask the user to enter a number from 1 to 10. The program will also generate a random number from 1 to 10, the program will then compare the user input and the generated number, the program must display a message if the user had guessed the number or not.
How to use randomize with the same value for number?
Using Randomize with the same value for Number does not repeat the previous sequence. This example uses the Rnd function to generate a random integer value from 1 to 6. Dim MyValue As Integer MyValue = Int ( (6 * Rnd) + 1) ‘ Generate random value between 1 and 6.
How to repeat a random number in vbmath?
If Randomize is not used, the Rnd function (with no arguments) uses the same number as a seed the first time it is called, and thereafter uses the last-generated number as a seed value. To repeat sequences of random numbers, call Rnd with a negative argument immediately before using Randomize with a numeric argument.
How does the randomize function in vbmath work?
Instead, the value returned by the system timer is used as the new seed value. If Randomize is not used, the Rnd function (with no arguments) uses the same number as a seed the first time it is called, and thereafter uses the last-generated number as a seed value.
How to generate a random value in vbmath?
Randomize () ‘ Generate random value between 1 and 6. Dim value As Integer = CInt(Int ( (6 * Rnd ()) + 1)) This overload of the Randomize method does not take a seed value. Instead, the value returned by the system timer is used as the new seed value.
How to dim a random integer in VB.NET?
Dim randoms(1000) As Integer For i As Integer = 0 to randoms.Length – 1 randoms(i) = GetRandom(1, 100) Next The following code addresses this issue:
How to initialize a random number generator in Visual Basic?
Visual Basic Initializes the random-number generator. Initializes the random-number generator. Initializes the random-number generator. Initializes the random-number generator. This example uses the Randomize statement to initialize the random-number generator.
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Random Number Generators QuickStart Sample (Visual Basic)
Illustrates how to use specialized random number generator classes in the Extreme.Statistics.Random namespace in Visual Basic.
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VBMath. Randomize Method
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Initializes the random-number generator.
Randomize()
This example uses the Randomize statement to initialize the random-number generator. Because the number argument has been omitted, Randomize uses the return value from the Timer function as the new seed value.
This overload of the Randomize method does not take a seed value. Instead, the value returned by the system timer is used as the new seed value.
If Randomize is not used, the Rnd function (with no arguments) uses the same number as a seed the first time it is called, and thereafter uses the last-generated number as a seed value.
To repeat sequences of random numbers, call Rnd with a negative argument immediately before using Randomize with a numeric argument.
Because the Random statement and the Rnd function start with a seed value and generate numbers that fall within a finite range, the results may be predictable by someone who knows the algorithm used to generate them. Consequently, the Random statement and the Rnd function should not be used to generate random numbers for use in cryptography. For more information, see RandomNumberGenerator .
- Math Summary
Randomize(Double)
Optional. An Object or any valid numeric expression.
Randomize uses Number to initialize the Rnd function's random-number generator, giving it a new seed value. If you omit Number , the value returned by the system timer is used as the new seed value.
To repeat sequences of random numbers, call Rnd with a negative argument immediately before using Randomize with a numeric argument. Using Randomize with the same value for Number does not repeat the previous sequence.
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Generating a random number
Visual basic.
Random numbers can be generated by the Visual Basic Rnd() function, that returns a floating-point value between 0.0 and 1.0. Multiplying the random numbers will specify a wider range. For example, a multiplier of 20 will create a random number between zero and 20. To make the generated random number more useful, you can round it up to the nearest higher integer value with the Math.Ceiling() method so the range, in this case, becomes from 1 to 20.
The numbers generated by Rnd() are not truly random, but are merely a sequence of pseudo random numbers produced by an algorithm from a specific starting point. Whenever an application loads, a call to the Rnd() function will begin at the same starting point – so the same sequence will be repeated. This is not generally desirable, so the application needs to create a new starting point when it loads to avoid repetition. This can be achieved by calling the Randomize() function in the Form’s Load event, to “seed” the Rnd() function with a starting point based upon the system time when the application gets loaded – now the sequence of generated numbers is different each time.
Step 1 Add a Label , TextBox , and Button control to a Form, and arrange them like this:

Step 2 Name the Label control Msg, set its AutoSize property to False , then assign the text illustrated above to its Text property
Step 3 Name the TextBox control Guess, and set the Text property of the Button likewise

The numbers generated by the algorithm for Randomize() and Rnd() may be predicted, so this technique should not be used for cryptography.
Step 4 Click on View , Code to open the Code Editor , then create a variable in the Declarations
Dim num As Integer
Step 5 Still in the declarations section, add a Sub routine to assign a random number 1-20 to the num variable
Private Sub GetNumber() ____ num = Math.Ceiling( Rnd() * 20 ) End Sub
Step 6 In the Form’s Load event-handler, add a call to seed the random number generator and a call to set the num variable with an initial pseudo random value

Randomize() GetNumber()
Step 7 Now, add some logic to the Button control’s Click event-handler with this code
Select Case ( Val( Guess.Text) ) Case Is > num Msg.text = Guess.Text & “ is too high” Case Is < num Msg.Text = Guess.Text & “ is too low” Case Is = num Msg.Text = Guess.Text & “ is correct” & _ “I have thought of another number – Try again!” GetNumber() End Select Guess.Text = “”
Step 8 Run the application and guess the random number

The integer value must be extracted from the TextBox by the Val() function before making any comparison.

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Generating Random Numbers
VB provides a simple little function that lets you generate your own random (or as random as you can get on a PC!) numbers, called Rnd. Below is an example. For more information, click here.
Private Sub cmdRollDice_Click() Dim intResult As Integer '// Initializes the random-number generator, otherwise each time you run your '// program, the sequence of numbers will be the same Randomize intResult = Int((6 * Rnd) + 1) '// Generate random value between 1 and 6. MsgBox "Dice: " & intResult '// Display result End Sub Private Sub cmdGetRandomNumber_Click() Dim intResult As Integer '// Initializes the random-number generator, otherwise each time you run your '// program, the sequence of numbers will be the same Randomize intResult = Int((100 * Rnd) + 1) '// Generate random value between 1 and 100. MsgBox "Random number: " & intResult '// Display result End Sub
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VBA Random Number
This tutorial will demonstrate how to work with random numbers in VBA.
RND Function
The RND Function generates a number that is between 0 and 1. The syntax of the RND Function is:
Rnd([Number]) where:
- Number ( Optional) – This is optional and if <0, the function returns the same random number on each call using [Number] as the seed, if =0, the function returns the most recent random number, if >0 the function returns the next generated random number. If blank the default >0, is used.
Generating a Random Number in VBA
In order to generate a random number between two values, you have to use the RND Function in combination with the INT Function (Integer Function) using the following general formula:
- Int(lowerbound + Rnd * ( upperbound – lowerbound + 1 ) )
So, in order to generate a random number between 2 and 30, you would use the following code:
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Random Number Generator using VB.NET

- Public Class Form1
- Public random As New Random ( )
- Private Sub Button1_Click ( ByVal sender As System . Object , ByVal e As System . EventArgs ) Handles Button1 . Click
- Dim i As Integer
- For i = 1 To 3
- MsgBox ( Convert . ToString ( random . Next ( 0 , 1000 ) ) )

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- VB Random Number Generator
- Generating Random Number
- random number
Add new comment
The Random class is used to generate non-negative pseudo-random integers that are not truly random, but are for general purposes close enough.
The sequence is calculated using an initial number (called the Seed ) In earlier versions of .net, this seed number was the same every time an application was run. So what would happen was that you would get the same sequence of pseudo-random numbers every time the application was executed. Now, the seed is based on the time the object is declared.
# Declaring an instance
This declares an instance of the Random class called rng . In this case, the current time at the point where the object is created is used to calculate the seed. This is the most common usage, but has its own problems as we shall see later in the remarks
Instead of allowing the program to use the current time as part of the calculation for the initial seed number, you can specify the initial seed number. This can be any 32 bit integer literal, constant or variable. See below for examples. Doing this means that your instance will generate the same sequence of pseudo-random numbers, which can be useful in certain situations.
where x has been declared elsewhere in your program as an Integer constant or variable.
# Generate a random number from an instance of Random
The following example declares a new instance of the Random class and then uses the method .Next to generate the next number in the sequence of pseudo-random numbers.
The last line above will generate the next pseudo-random number and assign it to x . This number will be in the range of 0 - 2147483647. However, you can also specify the range of numbers to be generated as in the example below.
Please note however, that using these parameters, range of numbers will be between 15 or above and 199 or below.
You can also generate floating point numbers of the type Double by using .NextDouble e.g
You cannot however specify a range for this. It will always be in the range of 0.0 to less than 1.0.
Finally, a note about randomization. As mentioned earlier, when you declare an instance of Random without any parameters, the constructor will use the current time as part of the calculation to create the initial seed number. Normally this is OK.
However. If you re-declare new instances over a very short space of time, each time the seed number is calculated, the time could be the same. Consider this code.
Because computers are very quick these days, this code will take a fraction of a second to run and on several dequential iterations of the loop, the system time will not have changed. So, the seed number will not change and the random number will be the same. If you want to generate lots of random numbers, declare the instance of random outside the loop in this simple example.
The basic rule of thumb is don't re-instantiate random number generator over short periods of time.
← Recursion Classes →

IMAGES
VIDEO
COMMENTS
To produce random integers in a given range, use this formula: VB Int ( (upperbound - lowerbound + 1) * Rnd + lowerbound) Here, upperbound is the highest number in the range, and lowerbound is the lowest number in the range. Note
first open the visual basic program then drag a button onto the form and add a text box next double click on the button and once you're in the code building page, input this code line: Dim a as Integer Dim value As Integer = CInt (Int ( (10 * Rnd ()) + 1)) TextBox1.Clear () ' Initialize the random-number generator. Randomize ()
Rnd () generates a number n, 0<= n < 1 so if you want to generate a number between 1 and 10, you need to add +1, as multiplying Rnd () with 10 will give you numbers between 0 and 9. Share Improve this answer Follow edited Jul 25, 2017 at 12:46 boop_the_snoot 3,171 4 33 44 answered Jul 25, 2017 at 12:40 Rasmus Dalhoff-Jensen 51 8 Add a comment
How to generate a random value in vbmath? Randomize () ' Generate random value between 1 and 6. Dim value As Integer = CInt (Int ( (6 * Rnd ()) + 1)) This overload of the Randomize method does not take a seed value. Instead, the value returned by the system timer is used as the new seed value.
This example uses the Randomize statement to initialize the random-number generator. Because the number argument has been omitted, Randomize uses the return value from the Timer function as the new seed value. VB Dim MyValue Randomize ' Initialize random-number generator. MyValue = Int ( (6 * Rnd) + 1) ' Generate random value between 1 and 6.
Random Number Generator. - VB.NET RND To Generate Random Numbers.Visual Basic .NET Random Numbers - VB.NET TutorialsVB6 Random Number Generator Issue -Visual...
To produce random integers in a given range, use the following formula. VB randomValue = CInt(Math.Floor ( (upperbound - lowerbound + 1) * Rnd ())) + lowerbound Here, upperbound is the highest number in the range, and lowerbound is the lowest number in the range. Note
Quickstart sample (tutorial) that illustrates how to use specialized random number generator classes in the Extreme.Statistics.Random namespace in Visual Basic. Visual Basic - Random Number Generators - QuickStart Samples - Math, Statistics and Matrix Libraries for .NET in C#, VB and F#
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' Initialize the random-number generator. Randomize () ' Generate random value between 1 and 6. Dim value As Integer = CInt(Int ( (6 * Rnd ()) + 1)) Remarks Randomize uses Number to initialize the Rnd function's random-number generator, giving it a new seed value.
Visual Basic Random numbers can be generated by the Visual Basic Rnd () function, that returns a floating-point value between 0.0 and 1.0. Multiplying the random numbers will specify a wider range. For example, a multiplier of 20 will create a random number between zero and 20.
This is a simple video to show you how to make a random number generatorHere the script: Dim rndnumber As Random Dim number As Integer r...
Assign another random number to variable iRand before each of the statements where you use it. Create an array with four elements, and place a random number in each, then use those. (This is probably overkill, though.) Don't bother placing the number in a variable at all - just use the oRand.Next(1000, 9999) in each case.
VB provides a simple little function that lets you generate your own random (or as random as you can get on a PC!) numbers, called Rnd. Below is an example. For more information, click here. Private Sub cmdRollDice_Click() Dim intResult As Integer '// Initializes the random-number generator, otherwise each time you run your
Generating a Random Number in VBA In order to generate a random number between two values, you have to use the RND Function in combination with the INT Function (Integer Function) using the following general formula: Int (lowerbound + Rnd * ( upperbound - lowerbound + 1 ) )
Let's start with creating a Windows Form Application for this tutorial by following the following steps in Microsoft Visual Studio: Go to File, click New, and choose Windows Form Application . Next, add one button and named Button1. Have it also labeled as "Create Random Number". Follow this designed layout: Next, in the code tab, create a code ...
The Random class is used to generate non-negative pseudo-random integers that are not truly random, but are for general purposes close enough. The sequence is calculated using an initial number (called the Seed ) In earlier versions of .net, this seed number was the same every time an application was run.