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Case Study Questions Class 10 Science

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Download Case study questions for CBSE class 10 Science in PDF format from the myCBSEguide App . We have the new pattern case study-based questions for free download. Class 10 Science case study questions

This article will guide you through:

What are case study questions?

• Sample Papers with Case Study questions
• Class 10 Science Case Study question examples
• How to get case-based questions for free?
• How to attempt the case-based questions in Science?

Questions based on case studies are some real-life examples. The questions are asked based on a given paragraph i.e. Case Study.  Usually, 4-5 questions are asked on the basis of the given passage. In most cases, these are either MCQs or assertion & reason type questions. Let’s take an example to understand. There is one paragraph on how nitrogen is generated in the atmosphere. On the basis of this paragraph, the board asks a few objective-type questions. In other words, it is very similar to the unseen passages given in language papers. But the real cases may be different. So, read this article till the end to understand it thoroughly.

What is CBE?

CBSE stands for competency-based education. The case study questions are part of this CBE. The purpose of CBE is to demonstrate the learning outcomes and attain proficiency in particular competencies.

Questions on Real-life Situations

As discussed the case study questions are based on real-life situations. Especially for grade 10 science, it is very essential to have the practical knowledge to solve such questions. Here on the myCBSEguide app, we have given many such case study paragraphs that are directly related to real-life implications of the knowledge.

Sample Papers with Case Study Questions

Class 10 Science Sample Papers with case study questions are available in the myCBSEguide App . There are 4 such questions (Q.No.17 to 20) in the CBSE model question paper. If you analyze the format, you will find that the MCQs are very easy to answer. So, we suggest you, read the given paragraph carefully and then start answering the questions. In some cases, you will find that the question is not asked directly from the passage but is based on the concept that is discussed there. That’s why it is very much important to understand the background of the case study paragraph.

CBSE Case Study Sample Papers

You can download CBSE case study sample papers from the myCBSEguide App or Student Dashboard. Here is the direct link to access it.

Case Study Question Bank

As we mentioned that case study questions are coming in your exams for the last few years. You can get them in all previous year question papers issued by CBSE for class 1o Science. Here is the direct link to get them too.

Class 10 Science Case Study Question Examples

As you have already gone through the four questions provided in the CBSE model question paper , we are proving you with other examples of the case-based questions in the CBSE class 10 Science. If you wish to get similar questions, you can download the myCBSEguide App and access the Sample question papers with case study-type questions.

Case-based Question -1

Read the following and answer any four questions: Salt of a strong acid and strong base is neutral with a pH value of 7. NaCl common salt is formed by a combination of hydrochloride and sodium hydroxide solution. This is the salt that is used in food. Some salt is called rock salt bed of rack salt was formed when seas of bygone ages dried up. The common salt thus obtained is an important raw material for various materials of daily use, such as sodium hydroxide, baking soda, washing soda, and bleaching powder.

• Phosphoric acid
• Carbonic acid
• Hydrochloric acid
• Sulphuric acid
• Blue vitriol
• Washing soda
• Baking soda
• Bleaching powder

Case-based Question -2

• V 1  + V 2  + V 3
• V 1  – V 2  +V 2
• None of these
• same at every point of the circuit
• different at every point of the circuit
• can not be determined
• 20 3 Ω 203Ω
• 15 2 Ω 152Ω

Case-based Question -3

• pure strips
• impure copper
• refined copper
• none of these
• insoluble impurities
• soluble impurities
• impure metal
• bottom of cathode
• bottom of anode

How to Attempt the Case-Based Questions in Science?

Before answering this question, let’s read the text given in question number 17 of the CBSE Model Question Paper.

All living cells require energy for various activities. This energy is available by the breakdown of simple carbohydrates either using oxygen or without using oxygen.

See, there are only two sentences and CBSE is asking you 5 questions based on these two sentences. Now let’s check the first questions given there.

Energy in the case of higher plants and animals is obtained by a) Breathing b) Tissue respiration c) Organ respiration d) Digestion of food

Now let us know if you can relate the question to the paragraph directly. The two sentences are about energy and how it is obtained. But neither the question nor the options have any similar text in the paragraph.

So the conclusion is, in most cases, you will not get direct answers from the passage. You will get only an idea about the concept. If you know it, you can answer it but reading the paragraph even 100 times is not going to help you.

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CBSE Class 10 Science Case Study Questions Download Free PDF

If you are looking for the CBSE Class 10 Science Case Study Questions in PDF, then you are in the right place. CBSE 10th Class Case Study for the Science Subject is available here. These Case studies can help the students to solve the different types of questions that are based on the case study.

CBSE Board will be asking case study questions based on Science subjects in the upcoming board exams. Thus, it becomes an essential resource to study. 

The Science Subject case study for class 10th covers a wide range of chapters from the Science. Students willing to score good marks in their board exams can use it. The questions are highly interactive and it allows students to use their thoughts and skills to solve such kinds of questions.

Case Study Questions Class 10 Science

In board exams, students will find the questions based on assertion and reasoning . Also, there will be a few questions based on case studies. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

• Case Study Questions for Chapter 1 Chemical Reactions and Equations
• Case Study Questions for Chapter 2 Acids, Bases, and Salts
• Case Study Questions for Chapter 3 Metals and Non-Metals
• Case Study Questions for Chapter 4 Carbon and Its Compounds
• Case Study Questions for Chapter 5 Periodic Classification of elements
• Case Study Questions for Chapter 6 Life Processes
• Case Study Questions for Chapter 7 Control and Coordination
• Case Study Questions for Chapter 8 How do organisms reproduce?
• Case Study Questions for Chapter 9 Heredity and Evolution
• Case Study Questions for Chapter 10 Light reflection and refraction
• Case Study Questions for Chapter 11 Human eye and colorful world
• Case Study Questions for Chapter 12 Electricity
• Case Study Questions for Chapter 13 Magnetic effects of current
• Case Study Questions for Chapter 15 Our Environment

The above  Case studies  for CBSE Class 10 Science will help you to score good marks in the Case Study questions that have been coming in your examinations. These CBSE Class 10 Science Case Study have been developed by experts of cbseexperts.com   for benefit of Class 10 students.

Class 10 Science Assertion and Reason Questions

Case Study Type Questions in Science Class 10

Case Study Type Questions in Science Class 10 include the information or data. Students willing to solve them are required to read the passage carefully and then solve them. While solving the paragraph the ideal way is to highlight the key information or given data.

Because later it will ease them to write the final answers. Science Case study type questions consist of 4 to 5 questions that should be answered in an MCQ manner. 

While reading the paragraph students will get the clue in between about the possible answer of the question. They should definitely highlight those questions. This is the best way to solve such kind of Case study Type Questions.

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CBSE 10th Standard Science Subject Case Study Questions

By QB365 on 21 May, 2021

QB365 Provides the updated CASE Study Questions for Class 10 , and also provide the detail solution for each and every case study questions . Case study questions are latest updated question pattern from NCERT, QB365 will helps to get  more marks in Exams 

QB365 - Question Bank Software

10th Standard CBSE

Final Semester - June 2015

Redox reactions are those reactions in which oxidation and reduction occur Simultaneously. A redox reaction is made up of two half reactions. In the first half reaction, oxidation takes place and in second half reaction, reduction occurs. Oxidation is a process in which a substance loses electrons and in reduction, a substance gains electrons. The substance which gains electrons is reduced and acts as an oxidising agent. On the other hand, a substance which loses electrons is oxidised and acts as a reducing agent. (i) Which of the following is a redox reaction?

(ii) Identify the reaction in which H2 02 is acting as a reducing agent.

(iii) For the following reactions, identify the one in which H 2 S acts as a reducing agent.

(iv) For the following reaction, identify the correct statement. \(\mathrm{ZnO}+\mathrm{CO} \longrightarrow \mathrm{Zn}+\mathrm{CO}_{2}\)

(v) In the following reaction, which substance is reduced? \(\mathrm{PbS}+4 \mathrm{H}_{2} \mathrm{O}_{2} \longrightarrow \mathrm{PbSO}_{4}+4 \mathrm{H}_{2} \mathrm{O}\)

(ii) If the pH of a solution is 8, then its [H + ] ion is

(iii) In terms of acidic strength, which one of the following is in the correct increasing order?

(iv) Which of the following compounds does not give H + ions in aqueous solution?

(v) Four solutions labelled as P, Q, Rand Shave pH values 1, 9, 3 and 13 respectively. Which of the following statements about the given solutions is incorrect?

Baking powder produces carbon dioxide on heating, so it is used in cooking to make the batter spongy. Although, baking soda also produces CO 2 on heating, but it is not used in cooking because on heating, baking soda produces sodium carbonate along with carbon dioxide. Sodium carbonate, thus, produced, makes the taste bitter. Baking powder is the mixture of baking soda and a mild edible acid. Generally, tartaric acid is mixed with baking soda to make baking powder. When baking powder is heated, NaHCO 3 decomposes to give CO 2 which makes bread and cake fluffy. Tartaric acid helps to remove bitter taste due to formation of sodium tartrate. \(2 \mathrm{NaHCO}_{3}+ \ \ \mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{6} \quad \longrightarrow \quad 2 \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{Na}_{2} \mathrm{C}_{4} \mathrm{H}_{4} \mathrm{O}_{6}\) Baking soda         Tartaric acid            Carbon dioxide               Sodium tartrate (i) On passing excess CO 2 gas in aqueous solution of sodium carbonate, the substance obtained is

(ii) When sodium hydrogen carbonate is added to acetic acid, it evolves a gas. Which of the following statements are true about the gas evolved? (I) It turns lime water milky (II) It extinguishes a burning splinter (III) It dissolves in a solution of sodium hydroxide (IV) It has a pungent odour

(iii) Select the correct statement regarding sodium hydrogen carbonate.

(iv) Acetic acid was added to a solid X kept in a test tube. A colourless and odourless gas was evolved. The gas was passed through lime water which turned milky. It was concluded that

(v) Which of the following statements are correct regarding baking soda? (I) Baking soda is sodium hydrogen carbonate (II) On heating, baking soda gives sodium carbonate (III) It is used for manufacture of soap (IV) It is an ingredient of baking powder

The chemical reactivity of an element depends upon its electronic configuration. All elements having less than eight electrons in the outermost shell show chemical reactivity. During chemical reactions, atoms of all elements tend to achieve a completely filled valence shell. Metals are electropositive in nature. They have tendency to lose one or more electrons present in the valence shell of their atoms to form cations and achieve nearest noble gas configuration. The compounds formed by the transfer of electrons from one element to other are known as ionic or electrovalent compounds. (i) The electronic configurations of three elements X, Y and Z are:             X : 2                  Y: 2, 8, 7                     Z : 2, 8, 2 Which of the following is correct regarding these elements?

(ii) Element X reacts with element Y to form a compound Z. During the formation of compound Z, atoms of X lose one electron each whereas atoms of Y gain one electron each. Which of the following properties is not shown by compound Z?

(iii) Which of the following is correct representation of formation of magnesium chloride?

(iv) The electronic configuration of sodium ion is

(v)Which of the following represents an electropositive element?

A hydrocarbon (P) has the molecular formula C 10 H 22 .A hydrocarbon (Q) has two carbon atoms less than (P) and belong to the same homologous series. A hydrocarbon (R) has two carbon atoms more than (P) and belong to the same homologous series. (i) What is the molecular formula of (Q) ?

(ii) To which homologous series do the compound (P), (Q) and (R) belong?

(iii) What is the molecular formula of (R) ?

(iv) Identify the correct statement about compounds (P), (Q) and (R) .

(v) Compounds (P), (Q) and (R) are

The recurrence of properties of the elements after a certain regular intervals, when they are arranged in the increasing order of their atomic numbers, is called periodicity. There are a number of physical properties such as atomic size, metallic and non -metallic character, etc. which show periodic variation. In periodic table, various properties vary differently from moving left to right in a period and going down in a group. In a period, properties vary because from moving left to right in a period, number of shells remain same but valence electron increases by one number hence nuclear charge increases. In a group, on going down, number of valence shells increases while number of valence electrons remains same. (i) From top to bottom in a group of the periodic table, the electropositive character of the element

(ii) Which element has the largest size in the second period?

(iii) Which of the following elements has three valence electrons?

(iv) In the periodic table, the metallic character of elements (a) decreases from left to right and decreases down the group (b) decreases from left to right and increases down the group (c) increases from left to right and increases down the group (d) increases from left to right and decreases down the group (v) Which of the following increases along the period?

The small intestine is the longest part of the alimentary canal. It is a narrow tube of about 6 metres which lies coiled in the abdomen. The length of small intestine varies in different animals depending on the type of food they eat. (i) Humans are not able to digest cellulose whereas they are able to digest starch due to

(iii) Butter cannot be digested in the stomach as lipase and bile are(a) released in small intestine

(iv) Which of the following is a correct statement? (a) Herbivores have shorter small intestine as they eat grasses (b) Carnivores have larger small intestine as they eat meat (c) Herbivores have larger small intestine as they eat grasses (d) None of these (v) Various types of movements are generated by the ______ layer of the small intestine.

(iii) Which of the following animals shows double circulatory pathway?

(v) Select the option which properly represents pulmonary circulation in humans. \(\text { (a) Left auricle } \frac{\text { Deoxygenated }}{\text { blood }}{\longrightarrow} \text { Lungs } \frac{\text { Oxygenated }}{\text { blood }} \text { Right ventricle }\) \(\text { (b) Left auricle } \frac{\text { Oxygenated }}{\text { blood }}{\longrightarrow} \text { Lungs } \frac{\text { Deoxygenated }}{\text { blood }}{\longrightarrow} \text { Right ventricle }\) \(\text { (c) Right ventricle } \frac{\text { Deoxygenated }}{\text { blood }}{\longrightarrow} \text { Lungs } \frac{\text { Oxygenated }}{\text { blood }} \rightarrow \text { Left auricle }\) \(\text { (d) Right ventricle } \frac{\text { Oxygenated }}{\text { blood }}>\text { Lungs } \frac{\text { Deoxygenated }}{\text { blood }} \gg \text { Left auricle }\)

Spore formation, method of asexual reproduction is used by unicellular as well as multicellular organisms.Spores are microscopic units which could be air borne or are present in soil, etc. (i) A slice of bread kept in open for sometime shows growing white cottony mass which later turns black. This happens because (a) bacterial spores present in air germinate on the surface of bread slice (b) fungal spores present in air germinate on the surface of bread slice (c) protozoan microbes start feeding on bread slice (d) none ef these. (ii) Spore formation can be seen in

(iii) Bulb like structure at top of erect hyphae where spores are produced is

Gregor Mendel conducted hybridisation experiments on garden peas for seven years and proposed the laws of inheritance in living organisms. He investigated characters in the garden pea plant that were manifested as two opposing traits, e.g., tall or dwarf plants, yellow and green seeds, etc. (i) Among the seven pairs of contrasting traits in pea plant as studied by Mendel, the number of traits related to flower, pod and seed respectively were

(ii) The colour based contrasting traits in seven contrasting pairs, studied by Mendel in pea plant were

(iii) Refer to the given table of contrasting traits in pea plants studied by Mendel.

Which of the given traits is correctly placed? (a) (i), (ii) and (iii) only (b) (ii), (iii) and (iv) only (c) (ii) and (iii) only (d) (i), (ii), (iii) and (iv) (iv) Some of the dominant traits studied by Mendel were (a) round seed shape, green seed colour and axial flower position (b) terminal flower position, green pod colour and inflated pod shape (c) violet flower colour, green pod colour and round seed shape (d) wrinkled seed shape, yellow pod colour and axial flower position. (v) Which of the following characters was not chosen by Mendel?

(ii) The angle between the incident ray and the emergent ray is called

(iii) When a ray is refracted through a prism, then

(iv) The angle of deviation depends on

(v) The rectangular surfaces of a prism are known as

Some harmful non-biodegradable chemicals, i.e., pesticides (e.g., DDT) and heavy metals (e.g., mercury, arsenic cadmium, etc.) enter the bodies of organism through the food chain and go on concentrating at each trophic level. This phenomenon is called bio-magnification or biological magnification. (i) Refer to the given food chain Phytoplankton  \(\longrightarrow\) Zooplankton \(\longrightarrow\) Small fish \(\longrightarrow\)  Large fish \(\longrightarrow\) Fish eating birds If concentration of DDT in small fish is estimated to be 0.5 ppm, then amount of DDT in zooplankton and large fish would respectively be

(ii) Refer to the given table.

According to the given data. The correct order in a food chain will be

(iv) Higher amount of DDT disturb calcium metabolism of birds. This results in

(v) When animals are sprayed with poisons, they may die immediately, but their bodies still contain the poison. The poison in their bodies will then be passed on to the animals which eat them. What would be the consequence of a mass poisoning of the rabbit population in a grazing food chain and why? (a) Plants would die quickly as they are eaten by rabbits (b) Grasshopper would die quickly as all the animals in the food web would be affected (c) Western rattlesnakes would quickly become poisoned as they eat rabbits (d) Hawk would become poisoned as they feed on rabbits

(v) Greenhouse effect is due to

Energy flow is the key function of an ecosystem. It is determined by the two basic laws of thermodynamics. Flow of energy in our ecosystem is unidirectional. Green plants capture approximately about 1% of the solar energy incident on the earth to carry out the process of photosynthesis. In an ecosystem, transfer of energy follows 10 percent law, i.e., only 10% energy is transferred from one trophic level to another and remaining 90% of energy is lost in respiration. (i) Read the given statements and select the incorrect one(s). I. At each trophic level organisms utilise energy in respiration. II. Only 10 percent of the solar radiations that fall on earth is used by green plants. III. Green plants are the ultimate source of entire energy as most of the food chain begin with them. IV. A food chain usually consist of 3-4 trophic levels.

(ii) Refer to the given flow chart. Plants \(\rightarrow\)  Rat \(\rightarrow\)  Snake 20 units   2 units   0.2 unit The given flow chart states that (a) flow of energy in an ecosystem is unidirectional (b) as we move along in a food chain the number of individuals at each trophic level decreases (c) only 10% of the total energy becomes available to next trophic level (d) both (a) and (c). (iii) Nearly 90% of the energy is wasted while moving from one trophic level to other. This energy is used in

(v) Which of the following correctly states the processes involved in energy transfer between the trophic levels?

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Cbse 10th standard science subject case study questions answer keys.

(I) (b) : H 2 is oxidised to HCI while Cl 2 is reduced to HCl. (ii) (c) \((iii) (c): 2 \mathrm{Fe} \mathrm{Cl}_{3}+\mathrm{H}_{2} \mathrm{~S} \longrightarrow 2 \mathrm{FeCl}_{2}+2 \mathrm{HCl}+\mathrm{s}\) H 2 Sitself gets oxidised to Sand reduces FeCl 3 to FeCI 2 (iv) (a ): ZnO is reduced to Zn and CO is oxidised to CO 2 (v) (b) : H 2 O 2 is reduced to water by removal of oxygen.

(i) (c): As the pH value increases from 7 to 14, it represents decrease in H+ ion concentration in the solution. (ii)  (c) : pH = -log l0  [H + ] = 8 log l0  [H + ] =-8 [H + ] = 10 - 8 mol/L (iii) (a) (iv) (b): C 2 H 5 OH is not an ionic compound, it is a covalent compound and hence does not give H + ions in aqueous solution. (v) (c) : (a) Lower the pH of the solution, more acidic is the solution and higher is the [H + ] ions Thus, solution P (pH = 1) has higher [H + ] ions than solution R (pH = 3). (b) Higher the pH of the solution, more basic is the solution and higher is the [OH - ] ions Thus, solution Q (pH = 9) has lower [OH - ] ions than solution S (pH = l3). (c) Solution P (pH = 1) is acidic which turns blue litmus solution red whereas solution Q (pH = 9) is basic which turns red litmus solution blue. (d) Solution P (pH = 1) is highly acidic while solution S (pH = l3) is highly basic and solution Q (pH = 9) is weakly basic.

\({ (i) }(\mathrm{b}): \mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \longrightarrow 2 \mathrm{NaHCO}_{3}\)   (ii) (b) :  \(\mathrm{NaHCO}_{3}+\mathrm{CH}_{3} \mathrm{COOH} \longrightarrow \mathrm{CH}_{3} \mathrm{COONa}\)   \(+\mathrm{CO}_{2} \uparrow+\mathrm{H}_{2} \mathrm{O}\) Carbon dioxide gas is evolved which turns limewater milky. It extinguishes a burning splinter since it is not a supporter of combustion. It dissolves in sodium hydroxide solution and it is an odourless gas. \({ (iii) }(\mathrm{c}): 2 \mathrm{NaHCO}_{3} \stackrel{\text { Heat }}{\longrightarrow} \mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2}\) NaHCO 3 is soluble in water. \({ (iv) }(\mathbf{b}): \mathrm{NaHCO}_{3}+\mathrm{CH}_{3} \mathrm{COOH} \longrightarrow\)   \(\mathrm{CH}_{3} \mathrm{COONa}+\mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O}\) (v) (c): It is not used in manufacture of soap .

(i) (d) (Ii) (b): '2' is an ionic compound \({ (iii) }(\mathrm{a}): \mathrm{Mg} \longrightarrow \mathrm{Mg}^{2+}+2 e^{-}\)    \(\mathrm{Cl}+e^{-} \longrightarrow \mathrm{Cl}^{-}\)    \(\mathrm{Mg}^{2+}+2 \mathrm{Cl}^{-} \longrightarrow \mathrm{MgCl}_{2}\)              2,8,2           2,8                    2,8,7                    2,8,8  \((\text { iv })(\mathrm{d}): \mathrm{Na} \longrightarrow \mathrm{Na}^{+}+e^{-}\)                 2,8,1        2,8 (v) (c): (a) and (d) represent electronegative elements and (b) represents a noble gas.

(i) (c) : Molecular formula of (Q) is CSH1Sas it has two carbon atoms less than (P). (ii) (c): Compounds (P), (Q) and (R) are alkanes having general formula C n H 2n+2 . (iii) (a): Molecular formula of (R) is C 12 H 26  as it has two carbon atoms more than (P) (iv) (b): Compound (P), (Q) and (R) belong to same homologous series so they have different physical properties but similar chemical properties. They have same general formula C n H 2n+2 .They . differ by 2 carbon atoms and 4 hydrogen atoms. (v) (a)

(i) (a): As the size of the atom increases down the group, electropositive character increases. (ii) (c): Li is the first element of the second period. As the size decreases in the period from left to right, therefore, Li is the largest atom in the period. (iii) (c): Al (Z = 13) : 2, 8, 3 (iv) (b): Metallic character of elements decreases from left to right and increases down the group. (v) (a): As we move from left to right along a period, the number of valence electrons increases from 1 to 8.

(i) (a): In human, cellulose is indigestible as it cannot be broken into smaller molecules due to absence of cellulase enzyme. (ii) (b): Finger-like projections that come out from mucosa of intestine form villi. Cells lining the villi produce numerous microscopic projections called microvilli giving a brush border appearance which increase the surface area for absorption enormously. Villi has a good supply of capillaries and a large lymph vessel for absorption of nutrients. If the inner lining of the small intestine will be smooth, the surface for absorption will be reduced. (iii) (a) (iv) (c) (v) (b)

(i) (c): A- Artery: Carries blood from heart to different body parts. It is thick-walled and elastic. It acts as a "pressure reservoir" for maintaining the blood flow. B - Capillary : Nutrients, hormones, gases, etc. can diffuse into tissue cells through capillaries and vice versa. It is thin-walled, and only one cell layer thick resting on basement membrane. C - Vein: Brings blood from different body parts to the heart. It is thin-walled and act as low-resistance conduct for blood flow. D - Pulmonary vein: Two pulmonary veins from each lung transport the oxygenated blood to the left atrium. (ii) (d): In amphibians, the left atrium receives oxygenated blood from the gills/lungs/skin and the right atrium gets the deoxygenated blood from other body parts. However, they get mixed up in the single ventricle which pumps out mixed blood i.e., incomplete double circulation (iii) (d): Whale is a mammal and in mammals, two separate circulatory pathways are found - systemic circulation and pulmonary circulation. Oxygenated and deoxygenated bloods received by the left and right atria respectively pass on to the left and right ventricles. Thus, oxygenated and deoxygenated bloods are not mixed. This is referred to as double circulation. (iv) (a) (v) (c): Pulmonary circulation is the movement of blood between heart and lungs. During this pathway deoxygenated blood entering the right atrium, moves into the right ventricle. From here it moves through the pulmonary arch into the lungs for oxygenation. Then from lungs the oxygenated blood moves into the left atrium through pulmonary veins.

(i) (b): The tiny spores of bread mould (Rhizopus) are always present in air. On coming in contact with moist surface of bread slice they settle on it and germinate to form new fungal hyphae which first look like white cottony mass and later turns black. (ii) (a): Mucor (fungus) reproduces asexually through spore formation. (iii) (d) (iv) (c) : Bacteria produce endospore which is a dormant and tough structure that enables bacteria to remain dormant for extended periods under unfavorable conditions. (v) (d)

(i) (a) : Characters studied by Mendel are as follows:

(i) (a): The angle between the two refracting surfaces of a prism is called angle of prism. (ii) (b): The angle between the incident ray and the emergent ray is called angle of deviation. (iii) (d): As the ray of light enters from rarer medium (air) to denser medium (glass), the angle of incidence is more than angle of refraction. (iv) (c): More be the refractive index, more be the angle of deviation and it also depends on the refractive index of prism. (v) (c): The refraction of light takes place through rectangular surfaces.

(i) (c): No two magnetic field lines are found to cross each other. If two field lines crossed each other, it would mean that at the point of intersection, the compass needle would point in two directions at the same time, which is not possible. (ii) (d): The magnetic field and hence the magnetic line of force exist in all the planes all around the magnet. (iii) (d): The relative strength of the magnetic field is shown by the degree of closeness of the field lines and the direction of the magnetic field is obtained by tangent to the field lines at the point of intersect. (iv) (d): The magnetic field lines due to a bar magnet are closed continuous curves directed from N to S outside the magnet and directed from S to N inside the magnet. Hence option (d) is correct. v) (d): Inside a bar magnet, the direction of field lines is from south pole to north pole

(i) (a): Due to bio-rnagnification, the concentration of DDT will always be less in zooplanktons than large fish (ii) (c) (iii) (b) : Due to bio-rnagnification the nonbio-degradable chemicals such as DDT accumulate and go on concentrating at each trophic level. (iv) (d) : Higher amounts of DDT disturb calcium metabolism of birds resulting in thinning of egg shells and their prematllre breaking that kills the embryos. (v) (d)

( i) (b) : In the given pie chart, gases P, Q, Rand S respectively are CO 2 , CH 4 , CFCs and N 2 O. Methane is produced by incomplete combustion of biomass. (ii) (c): Methane (gas Q) is produced by incomplete biomass combustion and incomplete decomposition mostly by anaerobic methanogens. Flooded paddy fields, marshes and cattles are the major source of this gas. (iii) (c) : CO 2 is the principal greenhouse gas that helps to keep the earth warm. (iv) (d) (v) (c)

(i) (b): 1% of solar radiation is captured by plants. Sun is the ultimate source of all energy. (ii) (d) (iii) (d) (iv) (d): The given pyramid is pyramid of energy that shows the two basic laws of thermodynamics. (v) (c): Light energy from the sun is converted to chemical energy in producers via photosynthesis. This chemical energy is then transferred to primary consumer, then subsequently to secondary consumer via feeding.

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Important CBSE Class 10 Case Study Based Questions 2024: Source-Based Questions & Answers for Quick Revision

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Case Study Questions Class 10 Science Chapter 4 Carbon and Its Compounds

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CBSE Board Exam is on the way, so you must practice some good Case Study Questions Class 10 Science to boost your preparation to score 95+% on Boards. In this post, you will get Case Study and Passage Based Questions that will come in CBSE Class 10 Science Board Exams.

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In CBSE Class 10 Science Paper, Students will have to answer some questions based on  Assertion and Reason . There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

Carbon and its Compounds Case Study Questions With Answers

Here, we have provided case-based/passage-based questions for Class 10 Science  Chapter 4 Carbon and Its Compounds .

Case Study/Passage Based Questions

Question 1:

Read the following and answer any four questions from (i) to (v).

The compounds which have the same molecular formula but differ from each other in physical or chemical properties are called isomers and the phenomenon is called isomerism. When the isomerism is due to differences in the arrangement of atoms within the molecule, without any reference to space, the phenomenon is called structural isomerism . In other words. structural isomers are compounds that have the same molecular formula but different structural formulas, i.e., they are different in the order in which different atoms are linked. In these compounds, carbon atoms can be linked together in the form of straight chains, branched chains or even rings.

(i) Which of the following sets of compounds have the same molecular formula? (a) Butane and iso-butane (b) Cyclohexane and hexene (C) Propanal and propanone (d) All of these

Answer: (d) All of these

(ii) In order to form branching, an organic compound must have a minimum of (a) four carbon atoms (b) three carbon atoms (c) five carbon atoms (d) any number of carbon atoms.

Answer: (a) four carbon atoms

(iii) Which of the following is an isomeric pair? (a) Ethane and propane (b) Ethane and ethene (c) Propane and butane (d) Butane and 2-methylpropane

Answer: (d) Butane and 2-methylpropane

(iv) Among the following the one having longest chain is (a) neo-pentane (b) iso-pentane (C) 2-methylpentane (d) 2,2-dimethylbutane.

Answer: (C) 2-methylpentane

(v) The number of isomers of pentane is (a) 2 (b) 3 (c) 4 (d) 5

Answer: (b) 3

Question 2:

Food, clothes, medicines, books, or any of the things are all based on this versatile element carbon. In addition, all living structures are carbon-based. The earth’s crust has only 0.02% carbon in the form of minerals. The element carbon occurs in different forms in nature with widely varying physical properties. Both diamond and graphite are formed by carbon atoms, the difference lies in the manner in which the carbon atoms are bonded to one another. Carbon has the unique ability to form bonds with other atoms of carbon, giving rise to large molecules. This property is called catenation.

(i) From the given alternatives, whose chemical and physical properties are not the same? (a) Graphite and Diamond (b) Phosphorous and Sulphur (c) Carbon and Hydrogen (d) Methyl alcohol and Acetic acid

Answer: (d) Due to presence of different functional groups methyl alcohol and acetic acid. Possess different physical and chemical properties.

(ii) Which of the following statements is not correct? (a) Graphite is much less dense than diamond (b) Graphite is black and soft (c) Graphite has low melting point (d) Graphite feels smooth and slippery

Answer: (c) Graphite has low melting point

(iii) Which of the following are isomers? (a) Butane and isobutene (b) Ethane and ethene (c) Propane and propyne (d) Butane and isobutane

Answer: (d) Butane and isobutane have same chemical formula but different arrangement of atoms and have different structure.

(iv) Which one of the following is not an allotrope of carbon? (a) Soot (b) Graphite (c) Diamond (d) Carborundum

Answer: (d) Carborundum is SiC (silicon carbide).

(v) Pentane has the molecular formula C 5 H 12 . It has (a) 5 covalent bonds (b) 12 covalent bonds (c) 16 covalent bonds (d) 17 covalent bonds

Answer: (c) 16 covalent bonds

Question 3:

A homologous series is a series of organic compounds which belong to the same family (i.e. possess same functional group) and show similar chemical properties. The members of this series are called homologous and differ from each other by the number of CH 2  units in the main carbon chain.

3.1) Which of the following is not the property of a homologous series ? (a) They all contain double bond. (b) They differ by 14 units by mass. (c) They show similar chemical properties. (d) They can be represented by a general formula.

Answer: (a) They all contain double bond

3.2) Which of the following represent the name and formula of the 2nd member of homologous series having general formula C n H 2n + 2  ? (a) Methane CH 4 (b) Ethane C 2 H 6 (c) Ethyne C 2 H 6 (d) Ethene C 2 H 4

Answer: (b) Ethane C2H6

3.3) The chemical properties of which of the following compounds is similar to the butane ? (a) Propyne (b) Pentane (c) Butyne (d) Propene

Answer: (b) Pentane

3.4) The difference between two consecutive members in a homologous series in alkanes in terms of molecular mass and number of atoms of elements is : (a) 14 a.m.u and CH respectively (b) 12 a.m.u and CH respectively (c) 14 a.m.u and CH2 respectively (d) 12 a.m.u and CH3 respectively

Answer: (c) 14 a.m.u and CH2 respectively

3.5) Which of the following does not belong to the same homologous series ? (a) CH 4 (b) C 2 H 6 (c) C 3 H 8 (d) C 4 H 8

Answer: (d) C4H8

Question 4:

Some elements exist in various forms. These forms have different physical properties but have the same chemical properties. They are called allotropes of the element. Carbon, Phosphorous and sulphur have allotropes. Diamond and graphite are the allotropes of carbon. The differences in the physical properties of diamond and graphite are because of the manner in which the carbon atoms are arranged.

4.1) The hardest substance known which doesn’t conduct electricity is : (a) graphite (b) fullerence (c) diamond (d) methane

Answer:(c) diamond

4.2) Diamond is a : (a) three dimensional structure (b) one dimensional structure (c) two dimensional structure (d) none of these

Answer:(a) three dimensional structure

4.3) Graphite is used as a crucible to melt metals because : (a) it has low melting point (b) it has high boiling point (c) it has low boiling point (d) it has high melting point 

Answer:(d) it has high melting point

4.4) Which of the following is correct the structure of diamond ? (a) Carbon atoms are held together by single covalent bonds. (b) Carbon atoms conduct electricity in the molten state. (c) Layers of atoms slide easily over each other. (d) Electrons move freely through the structure.

Answer:(a) Carbon atoms are held together by single covalent bonds.

4.5) Diamond is not a good conductor of electricity because : (a) it is very hard. (b) it has no free electrons. (c) it is not water soluble. (d) its structure is very compact.

Answer:(b) it has no free electrons..

Hope the information shed above regarding Case Study and Passage Based Questions for Class 10 Science Chapter 4 Carbon and Its Compounds with Answers Pdf free download has been useful to an extent. If you have any other queries about CBSE Class 10 Science Carbon and Its Compounds Case Study and Passage Based Questions with Answers, feel free to comment below so that we can revert back to us at the earliest possible. By Team Study Rate

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Case Study Questions Class 10 Science Heredity and Evolution

Case study questions class 10 science chapter 9 heredity and evolution.

CBSE Class 10 Case Study Questions Science Heredity and Evolution. Term 2 Important Case Study Questions for Class 10 Board Exam Students. Here we have arranged some Important Case Base Questions for students who are searching for Paragraph Based Questions Heredity and Evolution.

At Case Study Questions there will given a Paragraph. In where some Important Questions will made on that respective Case Based Study. There will various types of marks will given 1 marks, 2 marks, 3 marks, 4 marks.

CBSE Case Study Questions Class 10 Science Heredity and Evolution

A scientist cross pure-bred tall (dominant) pea plant with pure-bred dwarf (recessive) pea plant he will get pea plants of F1 generation. If now self-cross the pea plant of F2 generation is done, then we obtain pea plants of F2 generation.

[KVS Raipur 2021-22]

(a) State the type of plants not found in F2 generation but appeared in F2 generation, mentioning the reason for the same

Answer – In the F1 generation, Dwarf trait is recessive trait which was not expressed. After self pollination, the recessive trait gets expressed in F2 generation

(b) State the ratio of tall plants to dwarf plants in F2 generation.. Write the full form of DNA.

Answer- Ratio – 3:1

Full form of DNA – Deoxyribonucleic acid

(c) What do the plants of F2 generation look like ?

Answer – All plants of F1 generation will be tall plants.

(c) How does the creation of variations in a species promote survival ?

Answer – Variations promote the survival only when the species wants to allow by itself for survive to the continuous changing environment and conditions. During variations, different species get different kinds of advantages depending on the nature.

Case Study – 2

Mendel was educated in a monastery and went on to study science and mathematics at the University of Vienna. Failure in the examinations for a teaching certificate did not suppress his zeal for scientific quest. He went back to his monastery and started growing peas. Many others had studied the inheritance of traits in peas and other organisms earlier, but Mendel blended his knowledge of science and mathematics and was the first one to keep count of individuals exhibiting a particular trait in each generation. This helped him to arrive at the laws of inheritance.

Based on the above information, answer the following questions.

(a) Why did Mendel select a pea plant for his experiments?

Answer- Mandel Selects pea plant for his experiment, because pea plant grown easily in few days and also has some interesting characters. And also, many generations can examined by Mendel in few days or months.

(b) Study the picture below that represents traits studied by Mendel in garden pea.

Answer- Yellow pod colour and axial position are dominant traits.

Case Study – 3

Pure bred pea plant with smooth seeds (dominant characteristic) were crossed with pure bred pea plant with wrinkled seeds (recessive characteristic) . The F1 generation was self pollinated to give rise to the F2 generation.

(a) What is the expected observation of the F1 generation of plants ? 

Answer – All of them have smooth seeds.

(b) What is the expected observation of the F2 generation of plants ?

Answer- ¼ of them have wrinkled seeds and ¾ of them have smooth seeds

(c) What will be the genotypic ration of F2 offspring , also mention whether it will be homozygous or heterozygous ?

Answer- Genotypic ratio = 1: 2: 1

• Homozygous dominant
• Heterozygous dominant
• Homozygous recessive

CASE STUDY : 4

It is all very well to say that very dissimilar looking structures evolve from a common ancestral design. It is true that analysis of the organ structure in fossils allows us to make estimates of how far back evolutionary relationships go. Are there any current examples of such a process? The wild cabbage plant is a good example. Humans have, over more than two thousand years, cultivated wild cabbage as a food plant, and generated different vegetables from it by selection. This is, of course, artificial selection rather than natural selection.

i) What was the evolution history of cabbage?

Ans: Earlier, the human beings cultivates the wild cabbage for food and had produced different varieties of cabbage by doing artificial selection. The different varieties were kohlrabi, cauliflower, broccoli, cabbage, red cabbage and kale.

ii) What is molecular phylogeny?

Ans? It is a method to gather information of an organism regarding their evolutionary relationship.

iii) What are the different methods for tracing the evolutionary relationship?

Ans: Looking into the data of homologous organ and analogous organ, fossil and embryo development.

iv) Do you agree with the term that ” evolution should not be equated with progress”?

Ans- Yes, evolution leads to more and more complex body design over time. It doesnt mean that older design are inefficient. For example, the bacteria the most primitive and simplest type of organism live in any harsh habitat and still they are surviving.

v) Give one examples of evolution by stages?

Ans: Earlier, birds have feather only for heating purpose but as time passes, they evolve and now the feathers are used for flight also.

CASE STUDY : 5

The evolutionary relationships of the species we see around us. It is a sort of going backwards in time. We can do this by identifying hierarchies of characteristics between species. Similarities among organisms will allow us to group them and then study the groups. For this, which characteristics decide more fundamental differences among organisms, and which ones decide less basic differences? What is meant by ‘characteristics’, anyway? Characteristics are details of appearance or behaviour; in other words, a particular form or a particular function. That we have four limbs is thus a characteristic

i) What is homologous organs?

Ans: The organs which have similar structure but different functions.

Eg: limbs of human, bird, frog and lizard

ii) What are fossil?

Ans: The preserved remains or traces of remains body parts of an organism is called fossil.

iii) What are analogous organ?

Ans: Different structure but  same function.

Eg: wings of bats and birds.

iv) How do we know how old the fossils are?

Ans: By using carbon dating , in these we used radioactive decay of carbon 14 isotopes.

v) What does it infer ” if more characteristics of two species are common”?

Ans: It means they are closely related and may one had evolved from other or both have common ancestors.

CASE STUDY : 6

The rules for inheritance of such traits in human beings are related to the fact that both the father and the mother contribute practically equal amounts of genetic material to the child. This means that each trait can be influenced by both paternal and maternal DNA. Thus, for each trait there will be two versions in each child. What will, then, the trait seen in the child be?

i) What were the contrasting traits used by mendel?

Ans: Tall and dwarf plant, round/ wrinkled seeds, white / violets flower and on the basis of pod colour etc.

ii) What was the phenotypic ratio of monohybrid cross?

Ans: 3:1 here, 3 is for tall plants and 1 is dwarf plants.

iii) What was the genotypic ratio of monohybrid cross?

iv) How does the traits get expressed?

Ans: Genes control traits, the diploid organism inherit two alleles from a gene i.e one is from father and one is from mother.

v) Write the monohybrid cross between tall and dwarf plants?

Ans: TT × tt 👇 👇 F1:   Tt × Tt 👇 F2: TT   Tt    Tt     tt

CASE STUDY : 7

The two sexes participating in sexual reproduction must be somewhat different from each other for a number of reasons. How is the sex of a newborn individual determined? Different species use very different strategies for this. Some rely entirely on environmental cues. Thus, in some animals like a few reptiles, the temperature at which fertilised eggs are kept determines whether the animals developing in the eggs will be male or female. In other animals, such as snails, individuals can change sex, indicating that sex is not genetically determined. However, in human beings, the sex of the individual is largely genetically determined. In other words, the genes inherited from our parents decide whether we will be boys or girls.

i) How many chromosomes are there in human beings?

Ans: 23 pairs in which 22 pairs are autosomal and one pair i.e 23rd pair is sex chromosome.

ii) What are the pair of sex chromosome present in both male and female?

Ans: People have same set of chromosome i.e XX but male have different sets of chromosome i.e XY.

iii) How is the sex of the child determined in human beings?

Ans: The sex is determined by paternal chromosome i.e XY if X alleles fused with X chromosome of female then it is a baby girl. If Y allele fuse with X chromosome of female during fertilisation then it will be a baby boy.

iv) Give a cross between male and female for sex determination in human beings.

Ans:   XX         ×          XY

👇                   👇

X                  X       Y

XX            XY

(female)      (male)

v) What is hermaphrodites?

Ans: Those organisms who dont have seperate sex organs i.e both the sex organs are present in the same body.

Eg- Earthworm

CASE STUDY : 8

Change in non-reproductive tissues cannot be passed on to the DNA of the germ cells. Therefore the experiences of an individual during its lifetime cannot be passed on to its progeny, and cannot direct evolution. Consider another example of how an individual cannot pass on to its progeny the experiences of its lifetime. If we breed a group of mice, all their progeny will have tails, as expected. Now, if the tails of these mice are removed by surgery in each generation, do these tailless mice have tailless progeny? The answer is no, and it makes sense because removal of the tail cannot change the genes of the germ cells of the mice.

i) What are acquired traits? Explain with example.

Ans: The traits which are gain while experiencing the life time, its not related to genetic material.

Eg-  If a person get injured during his life time and get handicapped. This trait will not pass to his progeny as it had acquired throughout his life.

ii) Who wrote origin of life on earth?

Ans: Charles Darwin

iii) What do you meant by term speciation?

Ans: It is an evolutionary process in which new species are formed by developing distinct features from their species or by modifying their genetic material.

iv) What are the factors that gave rise to the formation of new species?

Ans: Geographical isolation, genetic drift, mutation and natural selection.

v) What is natural selection?

Ans: The process which occurs in nature by which organism adapt the changing environment and tend to survive in it and reproduce in it.

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Case Study Questions for Class 10 Science Chapter 1

Case Study Questions for Class 10 Science Chapter 1 Chemical Reactions and Equations  provided below is very helpful to understand the new format of Board Exams.  Case Study Questions for class 10 Chemistry  is a very trustable source for practice.  Class 10 Science Chapter 1 Case Study Questions  is provided to you by NCERT HUB.

Solve the given  Case Study Questions for Class 10 Science Chapter 1   to enhance your performance in the upcoming Board Exam.  Case Study Questions for Class 10 Chemical Reactions and Equations  is very important as these types of questions will be asked in the Board Exam.

Case Study Questions for Class 10 Science Chapter 1 Chemical Reactions and Equations

1. Read the following and answer the questions from 1.1 to 1.5 :

Amit took a lime solution and passed a gas ‘X’ through it. The solution becomes turgid. This solution was then divided into two parts. In the first part, more of gas ‘X’ was passed. While in the second part concentrated sulphuric acid was added. A white precipitate was formed in second part.

1.1) The gas mentioned in above passage is : (a) O₂ (b) H₃S (c) CO₂ (d) H₂ Answer

1.2) Lime water and chlorine reacts to form : (a) CaCl₂ (b) CaOCl₂ (c) CaO (d) CaCO Answer

1.3) A solution of a substance X is used for white washing. Identify X : (a) CaO (b) Ca(OH)₂ (c) CaCO₃ (d) CO₂

1.4) Ca(HCO₃) is : (a) insoluble in water (b) soluble in water (c) partially soluble in water (d) partially insoluble in water Answer

1.5) Lime water turns milky in the reaction due to the : (a) oxygen gas is evolved (b) formation of calcium bicarbonate (c) CO₂ gas is evolved (d) formation of calcium carbonate Answer

Please share Case Study Questions for Class 10 Science Chapter 1 with your friends !

2. Read the following and answer the questions from 2.1 to 2.5 :

In decomposition reactions, a single reactant breaks down to form two or more products. Decomposition reaction is opposite to combination reaction. Thermal decomposition reactions use the energy in form of heat for decomposition of reactants. Electrolytic decomposition reactions involve the use of electrical energy for the decomposition of reactant molecules. Photolysis or or photochemical decomposition involves the use of light energy for the purpose of decomposition.

2.1) Which of the following reactions is a decomposition reaction ? (a) NaOH + HCl → NaCl + H₂O (b) NH₄CNO → H₂NCONH₂ (c) 2KClO₃ → 2KCl + 3O₂ (d) H₂ + I₂ → 2HI Answer

2.2)  2Pb(NO3 )2 → 2PbO + nA + O₂. What is nA in the given reaction ? (a) NO₂ (b) 2PbNO₂ (c) 4NO₂ (d) 4NO Answer

2.3) Amino acid is formed by the decomposition of which component of our diet ? (a) Fat (b) Protein (c) Starch (d) Carbohydrate Answer

2.4) Silver chloride on exposure to sunlight for a long duration turns grey due to (i) the formation of silver by decomposition of silver chloride (ii) Sublimation of silver chloride (iii) decomposition of chlorine gas from silver chloride (iv) Oxidation of silver chloride. The correct statement(s) is / are :

(a) Only (iv) (b) Only (i) and (iii) (c) Only (ii) and (iii) (d) Only (i) and (ii) Answer

2.5) What type of chemical reaction takes place when electricity is passed through water ? (a) Displacement reaction (b) Photochemical decomposition (c) Electrolytic decomposition (d) Thermal decomposition Answer

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3. Read the following and answer the questions from 3.1 to 3.5 :

Redox reactions are those reactions in which oxidation and reduction occur simultaneously. A redox reaction is made up of two half reactions. In the first half reaction, Oxidation takes place and in second half reaction, reduction occurs. Oxidation is a process in which a substance loses electrons and in reduction, a substance hydrogen to a substance and removal of oxygen from a substance. 

The substance which gives oxygen to another substance or removes hydrogen from another substance in an oxidation reaction is known as oxidising agent, while the substance which gives hydrogen to another substance or removes oxygen from another substance in a reduction reaction is known as reducing agent. 

3.1) Which of the following is a redox reaction? (a) CaCO₃ → CaO + CO₂ (b) CaO + 2HCl → CaCl₂ + H₂O (c) H₂ + Cl₂ → 2HCl (d) NaOH + HCl → NaCl + H₂O Answer

3.2) Identify the reaction in which H₂O₂ is acting as a reducing agent. (a) Cl₂ + H₂O₂ → 2HCl + O₂ (b) 2FeCl₂ + 2HCl + H₂O₂ → 2FeCl₃ + 2H₂O (c) H₂SO₃ + H₂O₂ → H₂SO₄ + H₂O (d) 2HI + H₂O₂ → 2H₂O + I₂ Answer

3.3) For the following reaction, identify the correct statement.

                ZnO + CO → Zn + CO₂ 

(a) CO₂ is being oxidised. (b) ZnO is being reduced. (c) ZnO is being oxidised. (d) CO is being reduced. Answer

3.4) In the following reaction, which substance is reduced ?

            PbS + 4H₂O₂ → PbSO₄ + 4H₂O (a) PbSO₄ (b) PbS (c) H₂O (d) H₂O₂ Answer

3.5) For the following reactions, identify the one in which H₂S acts as a reducing agent . (a) CuSO₄ + H₂S → CuS + H₂SO₄ (b) Cd(NO₃)₂ + H₂S → CdS + 2HNO₃ (c) 2FeCl₃ + H₂S → 2FeCl₂ + 2HCl + S (d) None of these Answer

Practice Case Study Questions for Class 10 Science Chapter 1 to boost your score in Board Exam.

4. Read the following and answer the questions from 4.1 to 4.5 :

In a chemical reaction, reactants are converted into products. The conversion of reactants into products in a chemical reaction is often accompanied by some features. These features which take place as a result of chemical reaction are known as characteristics of chemical reactions. Some important characteristics of chemical reactions are : evolution of heat, change in colour, change in temperature etc.

4.1) Reaction of magnesium with air is : (a) exothermic reaction (b) substitution reaction (c) endothermic reaction (d) reversible reaction Answer

4.2) Which law is satisfied by a balanced chemical equation ? (a) Law of multiple proportions (b) Law of constant proportions (c) Law of conservation of mass (d) Law of conservation of chemical Answer

4.3) Which one of the following processes involve chemical reactions ? (a) Storing of Oxygen gas under pressure in a gas cylinder (b) Liquefication of air (c) Keeping petrol in china dish in the open (d) Heating copper wire in the presence of air at high temperature Answer

4.4) In which of the following reactions, high amount of heat energy will be evolved ? (a) Electrolysis of water (b) Burning of LPG (c) Decomposition of AgBr in the presence of light (d) Dissolution of NH₄Cl in water Answer

4.5) What type of chemical reaction takes place when electricity is passed through water ? (a) Thermal decomposition (b) Photochemical decomposition (c) Water decomposition (d) Electrolytic decomposition Answer

5. Read the following and answer the questions from 5.1 to 5.5 :

You must have observed that iron articles are shiny when they are new, but get coated with a reddish brown powder when left for sometime. This process is commonly known as rusting of iron. Some other metals also get tarnished in the same manner. When a metal is attacked by substances around it such as moisture, its said to corrode and this process is called corrosion. The black coating on silver and the green coating on copper are some examples of corrosion.

5.1) Chemically rust is : (a) hydrated ferrous oxide (b) hydrated ferric oxide (c) only ferric oxide (d) None of these Answer

5.2) Rusting of iron involves a chemical reaction which is a combination of : (a) Oxidation as well as combination reactions (b) Reduction as well as displacement reactions (c) Oxidation as well as displacement reactions (d) Reduction as well as combination reactions Answer

5.3) Rusting of iron takes place in : (a) ordinary water (b) distilled water (c) Both (a) and (b) (d) None of these Answer

5.4) Silver articles turns black when kept in the open for a few days due to formation of : (a) Ag₂S (b) H₂S (c) AgS (d) AgSO₄ Answer

5.5) Copper objects lose their shine and form green coating of : (a) copper oxide (b) copper carbonate (c) basic copper carbonate (d) copper hydroxide and copper oxide Answer

We hope the given  Case Study Questions for Class 10 Science Chapter 1 Chemical Reactions and Equations  provided below is very helpful to understand the new format of Board Exams. Case Study Questions for class 10 Chemistry Chapter 1 is a very trustable source for practice. If you have any queries regarding Case Study Questions for Class 10 Science Chapter 1, contact us and we will get back to you soon.

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Case Study and Passage Based Questions for Class 10 Science Chapter 2 Acids, Bases and Salts

• Last modified on: 2 days ago
• Reading Time: 8 Minutes

In CBSE Class 10 Science Paper, Students will have to answer some questions based on Assertion and Reason . There will be a few questions based on case studies and passage based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

Here, we have provided case based/passage based questions for Class 10 Science Chapter 2 Acids, Bases and Salts .

Case Study/Passage Based Questions on Acids, Bases and Salts

Case Study/Passage Based Questions

Question 1:

pH is quite useful to us in a number of ways in daily life. Some of its applications are:

Control of pH of the soil : Plants need a specific pH range for proper growth. The soil may be acidic, basic or neutral depending upon the relative concentration of H* and OH-. The pH of any soil can be determined by using pH paper. If the soil is too acidic, it can be corrected by adding lime to it. If the soil is too basic, it can be corrected by adding organic manure which contains acidic materials.

Regaining shine of a tarnished copper vessel by use of acids : A copper vessel gets tarnished due to formation of an oxide layer on its surface. On rubbing lenion on the vessel, the surface is cleaned and the vessel begins to shine again. This is due to the fact that copper oxide is basic in nature, which reacts with the acid (citric acid) present in lemon to form a salt (copper citrate) which is washed away with water. As a result, the layer of copper oxide is removed from the surface of the vessel and the shining surface is exposed.

Self-defence by animals through chemical warfare : Stings of bees and ants contain methanoic acid. When stung, it causes lot of pain and irritation. This can be cured by rubbing the affected area with mild base like baking soda.

(i) When black copper oxide placed in a beaker is treated with dilute HCl, its colour changes to ( a) white (b) dark red (c) bluish green (d) no change.

(ii) P is an aqueous solution of acid and Q is an aqueous solution of base. When these two are diluted separately, then (a) pH of P increases while that of Q decreases till neutralisation. (b) pH of P decreases while that of Q increases till neutralisation. (C) pH of both P and Q decrease. (d) pH of both P and Q increase.

(iii) Which of the following acids is present in bee sting? (a) Formic acid (b) Acetic acid (c) Citric acid (d) Hydrochloric acid

(iv) Sting of ant can be cured by rubbing the affected area with soap because (a) it contains oxalic acid which neutralises the effect of formic acid (b) it contains aluminium hydroxide which neutralises the effect of formic acid (c) it contains sodium hydroxide which neutralises the effect of formic acid (d) none of these

(v) The pH of soil X is 7.5 while that of soil Y is 4.5. Which of the two soils, should be treated with powdered chalk to adjust its pH? (a) X only (b) Y only (c) Both X and Y (d) none of these

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3 thoughts on “ Case Study and Passage Based Questions for Class 10 Science Chapter 2 Acids, Bases and Salts ”

question no. 1 bit (iii) answer is wrong. It will be option (a). Otherwise you had done a great job for students.

That answer of question 3 in 1 case study is incorrect it should be formic acid Hope that would be corrected… Thank you for your efforts 😊

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